
Regular polygon construction problem. Using compass and straightedge, construct a regular polygon with n sides.
First of all, we note that equilateral triangle and square are the two figures that can be easily constructed. We will call a polygon with n sides an n-gon and make the following observation
Observation: If we can construct a regular n-gon then we can also construct a regular 2n-gon.
Why is that? That is because if we have a regular n-gon then we can construct its circumcircle, and then at each side, we construct the perpendicular bisector to bisect the corresponding circle arc, then we will have a regular 2n-gon!

With the above simple observation, from a regular 3-gon, we can construct regular 6-gons, regular 12-gons, regular 24-gons, etc.
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triangle \rightarrow hexagon \rightarrow dodecagon |
And from "2-gon", we can construct regular 4-gons, regular 8-gons, regular 16-gons, etc.
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2-gon \rightarrow square \rightarrow octagon |
Thus, we have reduced the problem to the case when n is an odd number. For instance, if we want to construct a regular polygon with 68 sides, then we only need to find a way to construct a regular polygon with 17 sides. This is because 68 = 17 \times 2 \times 2, so from 17-gon, we obtain 34-gon, and then 68-gon!
Problem. For an odd number n, construct a regular polygon with n sides.
This turns out to be an extremely hard problem!
For a long time, we know how to construct a regular pentagon. In his glorious books, the Elements, Euclid of ancient Greek presented a method of constructing a regular pentagon by compass and straightedge. But for the next two thousand years, no one had ever succeeded in constructing a regular 7-gon, a regular 9-gon, or a regular 11-gon. Every effort seems to end up in failure.
The reason is not because of our incapability but it turns out that it is impossible to construct those polygons!
The first mathematician that made a breakthrough is Gauss. Gauss is often referred to as "the Prince of Mathematics". His Disquisitiones Arithmeticae, published when he was 24 years old, stands to this day as one of the most important book in mathematics.
When he was 19 years old, Gauss made a major discovery in mathematics - the construction of a regular 17-gon. It is believed that the excitement of this discovery had led Gauss to choose mathematics instead of philosophy as a career. Gauss was so pleased by this result that he requested that a regular 17-gon be inscribed on his tombstone. For some unknown reason, this request was not fulfilled, but on Gauss's memorial stone in Brunswick we can find a 17-point star!
This is Gauss' ground-breaking theorem:
Gauss' Theorem. If n = p_1 \dots p_t where p_1, ..., p_t are distinct Fermat primes then a regular n-gon can be constructed by compass and straightedge.
Later in 1837, Wantzel, a French mathematician, established the opposite direction of the theorem, that is, for an odd number n, if a regular n-gon is constructible then n must have the form n = p_1 \dots p_t as above.
Fermat's primes
Most of us probably have heard about the Fermat's last problem
The Fermat problem. Prove that for any n \geq 3, the following equation has no non-zero solutions x^n + y^n = z^n.
The Fermat's last problem had frustrated generations of mathematicians. It had attracted so much effort from top mathematicians as well as young school students. This is probably because it is stated so simple and neat. But the most likely reason is that it is a "mathematical mystery". Fermat wrote this problem on the margin of a book. He wrote that he had found a very beautiful proof but couldn't write it down because "there wasn't enough space" on the margin!
In 1994, Andrew Wiles - an English mathematician finally solved it. The proof employs some of the most powerful tools of modern mathematics. So Fermat's story is still a mystery!
Fermat was actually not a professional mathematician. He was a lawyer and he was doing math probably just for fun. He often communicated his results to other mathematicians of his time. "Ninety-nine times out of a hundred" Fermat was correct in his mathematical discoveries, but there was one time when he was wrong! This is about the Fermat's primes that we are about to discuss.
Since prime numbers serve as the building blocks for the entire natural numbers, mathematicians are keen on finding properties and formulas for primes. Fermat predicted that the numbers of the form F_n = 2^{2^n}+1
are prime numbers. If this was true then it would be a very nice formula for prime numbers. But unfortunately, this conjecture is not correct.
- n=0, F_0 = 2^{2^0}+1 = 2^1 + 1 = 3 is a prime,
- n=1, F_1 = 2^{2^1}+1 = 2^2 + 1 = 5 is a prime,
- n=2, F_2 = 2^{2^2}+1 = 2^4 + 1 = 17 is a prime,
- n=3, F_3 = 2^{2^3}+1 = 2^8 + 1 = 257 is a prime,
- n=4, F_4 = 2^{2^4}+1 = 2^{16} + 1 = 65537 is a prime,
- n=5, F_5 = 2^{2^5}+1 = 2^{32} + 1 = 4294967297 is a composite number!
The mathematician Euler pointed out that F_5 = 2^{2^5}+1 is a composite number as F_5 = 2^{2^5}+1 = 641 \times 6700417.
We have the following definition.
Fermat's prime. A prime number is called a Fermat's prime if it has the form F_n = 2^{2^n}+1.
Gauss-Wantzel Theorem
Going back to the problem of constructing regular polygons, the answer for the problem is the following theorem
Gauss-Wantzel's Theorem. For an odd number n, a regular polygon of n sides can be constructed by compass and straightedge if and only if n = p_1 \dots p_t, where p_1, ..., p_t are distinct Fermat's primes.
- 3 \times 5 = 15 so regular 15-gons are constructible,
- 3 \times 17 = 51 so regular 51-gons are constructible, etc...
On the other hand,
- regular 7-gons are not constructible,
- 9 = 3 \times 3 so regular 9-gons are not constructible,
- regular 11-gons are not constructible,
- regular 13-gons are not constructible, etc...
With the polygons that are constructible, how can they be constructed? For instance, how can we construct a regular polygon with 15 sides or 17 sides? With the polygons that cannot be constructed, is there a method to construct them approximately with a small error?
There are many interesting questions need to be answered. However, we will save it for our next posts. Let us stop here for now. See you next time.
There are many interesting questions need to be answered. However, we will save it for our next posts. Let us stop here for now. See you next time.
Homework.
Note that for the following problems, some of them have solutions, but some of them are open problems. However, we will not reveal it here and encourage readers to solve them all!
1. Prove that if 2^a + 1 is a prime then either a=0 or a=2^n.
2. Prove that there are infinitely many primes of the form 2^a + 1.
3. Prove that there are infinitely many composite numbers of the form 2^a + 1.
4. Prove that for any n > 1, the last digit of the Fermat number F_n = 2^{2^n}+1 is 7.
5. Prove that there are infinitely many numbers n such that the Fermat number F_n = 2^{2^n}+1 is a composite number.
6. Prove that for any n > 1, the Fermat number F_n = 2^{2^n}+1 cannot be written as a sum of two primes.
7. Find all pairs of numbers n and m such that F_n F_m is a perfect square.
8. Prove that for any n, the Fermat number F_n = 2^{2^n}+1 is not a cubed number.
9. Prove that the Fermat number F_{2014} = 2^{2^{2014}}+1 is a composite number.
10. Go to google.com and search about Gauss' 17-gon construction.